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Calcualte the time required for the initial concentration of `2.0 mol//dm^(3)` to get reduced to `1.2 mol//dm^(3)`. Given specific rate constant(k) = `0.009 min^(-1)` |
Answer» For a first order reaction, `t=(2.303)/(k) log(2.0 mol dm^(-3))/(1.2 mol dm^(-3))` `(2.303)/(0.09 min^(-1)) log 1.66=(2.303)/(0.009min^(-1)) xx 0.2218=56.8 min` |
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