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calculate-4. A tain starts from rest and attains a speed of 54 km/ h in 10 secondsa) the acceleration and54bj distance covered by the trainan

Answer»

speed of train is 54km/h , so in m/s the speed will be 54*5/18 = 15m/s

now acceleration is =v/t =15/10 = 1.5m/s².

distance travelled is s = 1/2at² = 1/2*1.5*10*10 = 75m



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