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calculate athe electric current density of uniform wire connected to a battery of emf 3.5V and negligible internal resistance.The resistance of the wire is 2.0 ohm and its area of coss section is 0.70 x10^-6 m^2 |
Answer» given,EMF of battery = 3.5 vResistance of the wire = 2.0 ohmsArea of cross section = 0.70*10^-6m^2Current,I = V/R ==>3.5/2 ==>1.75Current DENSITY = J = I/A = 1.75/0.70*10^-6m^2i.e........... J = 2.5*10^6.hope thishelps uh dear ;)pls MARK as brainliest.......... |
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