InterviewSolution
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InterviewSolution
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Calculate `Delta_(f)H^(@)` (in kJ/mol) for `Cr_(2)O_(3)` from the `Delta_(r)G^(@)` and the `S^(@)` values provided at `27^(@)` `4Cr(s)+3O_(2)(g)rarr2Cr_(2)O_(3)(s)," "Delta_(r)G^(@)=-2093.4kJ//mol` `S^(@)("J//K mol") : S^(@)(Cr,s)=24," "S^(@)(O_(2),g)=205," "S^(@)(Cr_(2)O_(3),s)=81`A. `-2258.1 kJ//mol`B. `-1129.05 kJ//mol`C. `-964.35 kJ//mol`D. `3462kJ//mol` |
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Answer» Correct Answer - B `Delta_(r)G^(@) = Delta_(r)H^(@)-T xx Delta_(r)S^(@)` `Delta_(r)S^(@) = 2 xx 81 -4xx 24 -3 xx 205 J//mol` `:. Delta_(r)H^(@) = -2258.1 kJ//mol` `Delta_(r)H^(@) = 2 xx Delta_(f)H^(@)(Cr_(2)O_(3), s)` `:. Delta_(f)H^(@)(Cr_(2)O_(3), s) = -(2258.1)/(2)` `= -1129.05 kJ//mol`. |
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