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Calculate `Delta_(r)G^(Theta)` at `298K` for the following reaction if the reaction mixtur econsists of `1atm` of `N_(2),3` atm of `H_(2)`, and `1atm` of `NH_(3)`. `N_(2)(g) +3H_(2)(g) W hArr 2NH_(3)(g), Delta_(r)G^(Theta) =- 33.32 kJ` |
Answer» `N_(2)(g) +3H_(2)(g) hArr 2NH_(3)(g), Delta_(r)G^(Theta) =- 33.32 kJ` Using: `Delta_(r)G = Delta_(r)G^(Theta) +RT In Q` where `Q = Q=(p^(3)underset(NH_(3)).)/(p_(N_(2)p_(H_(2)))) = (1^(2))/(1xx3^(2)) = (1)/(27)`, `T = 298 K: R = 8.314 J mol^(-1)K^(-1)` `rArr Delta_(r)G =- 33.2 +(8.314 xx 10^(-5)) xx 298 xx 2.303 log_(10).(1)/(27)` `rArr -33.2 - 8.16 = - 41.36 kJ mol^(-1)` |
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