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Calculate `DeltaG` and `DeltaG^(@)` for the reaction `: A + B hArr C + D` at `27^(@)C` .Equilibrium constnat`(K)` for this reaction `= 10^(2)`

Answer» `DeltaG = 0` because the reactin is in equilibrium.
`DeltaG^(@) = - 2.303 RT logK = -2.303 xx 8.314 JK^(-1) mol^(-1) xx 300 K log 10^(2)`
`= - 1148 J mol^(-1) = - 11.488 kJ mol^(-1)`


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