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Calculate `DeltaG` and `DeltaG^(@)` for the reaction `: A + B hArr C + D` at `27^(@)C` .Equilibrium constnat`(K)` for this reaction `= 10^(2)` |
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Answer» `DeltaG = 0` because the reactin is in equilibrium. `DeltaG^(@) = - 2.303 RT logK = -2.303 xx 8.314 JK^(-1) mol^(-1) xx 300 K log 10^(2)` `= - 1148 J mol^(-1) = - 11.488 kJ mol^(-1)` |
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