Calculate `DeltaH_(f)^(@)` for `Ubr_(4)` from the `DeltaG^(@)` of reaction and the `S^(@)` values at 298 K. `U(s)+2Br_(2)(l)rarrUBr_(4)(s), DeltaG^(@)=-788.6 kJ. " "S^(@)(J//K-"mol")50.3, 152.3, 242.6`A. `-822.1 kJ//mol`B. `-841.2 kJ//mol`C. `-775.6 kJ//mol`D. `-804.3 kJ//mol`

Calculate `DeltaH_(f)^(@)` for `Ubr_(4)` from the `DeltaG^(@)` of reac

1.	Calculate `DeltaH_(f)^(@)` for `Ubr_(4)` from the `DeltaG^(@)` of reaction and the `S^(@)` values at 298 K. `U(s)+2Br_(2)(l)rarrUBr_(4)(s), DeltaG^(@)=-788.6 kJ. " "S^(@)(J//K-"mol")50.3, 152.3, 242.6`A. `-822.1 kJ//mol`B. `-841.2 kJ//mol`C. `-775.6 kJ//mol`D. `-804.3 kJ//mol`
Answer» Correct Answer - A `DeltaG=DeltaH-TDeltaS` `DeltaS=242.6-50.3 -(2xx152.3), DeltaS=-112.3` `DeltaG=-788.6xx1000=DeltaH+298xx112.3` `DeltaH=-788.6 xx 1000 -298 xx 112.3` `DeltaH=-822.1 " kJ mol"^(-1)`

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Calculate `DeltaH_(f)^(@)` for `Ubr_(4)` from the `DeltaG^(@)` of reaction and the `S^(@)` values at 298 K. `U(s)+2Br_(2)(l)rarrUBr_(4)(s), DeltaG^(@)=-788.6 kJ. " "S^(@)(J//K-"mol")50.3, 152.3, 242.6`A. `-822.1 kJ//mol`B. `-841.2 kJ//mol`C. `-775.6 kJ//mol`D. `-804.3 kJ//mol`

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