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Calculate `DeltaU and DeltaH` when `10dm^(3)` of helium at NTP is heated in a cylinder to `100^(@)C`, assuming the the gas behaves ideally. `(C_(V)=3//2R)` |
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Answer» Correct Answer - `DeltaU=556.74J` `DeltaH=927.9J` `DeltaU=n*C_(V)*DeltaT and DeltaH=n*C_P*DeltaT` `=(10)/(22.4)xx(3)/(2)xx8.314xx100=556.74J` `=(10)/(22.4)xx(5)/(2)xx8.314xx100` `=927.9J` |
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