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For the reaction: `2H_(2)(g) +O_(2)(g) rarr 2H_(2)O(g), DeltaH =- 571 kJ` bond enegry of `(H-H) = 435 kJ` and of `(O=O) = 498 kJ`. Then, calculate the average bond enegry of `(O-H)` bond using the above data.A. 484 kJB. `-484kJ`C. `271kJ`D. `-271kJ` |
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Answer» Correct Answer - A `2(H-H)+O=Oto2(H-O-H)` `DeltaH=sum(BE)_("reactants")-sum(BE)_("products")` `=571=[2xx435+498]-4xx(BE)_(O-H)` `(BE)_(O-H)=(2xx435+498+571)/(4)=~~484kJ` |
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