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Calculate `E_(cell)^(0)` of (at 298K) `Zn(s)//ZnSO_(4)(aq)||CuSO_(4)(aq)//Cu(s)` given that `E_(Zn//Zn^(2+)(aq))^(0)=0.76V` `E_(Cu(s)//Cu^(2+)(aq))^(0)=-0.34V` |
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Answer» `E_(cell)^(0)=(S.R.P)_("cathode")-(S.R.P)_("anode")` `=0.34-(-0.76)=1.1V` |
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