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Calculate electric field intensity due to 2micro coloum of charge at distance 10mtr?​

Answer» TION:AnswerElectric field at(i) Point P DUE to CHARGE at A or C isE PA =E PC =9×10 9 × ( 2 ) 2 2 ×10 −6 = 29 2 ×10 3 NC −1 (ii) Point P due to charge at B is E PB =9×10 9 × (1) 2 2 2 ×10 −6 =18 2 ×10 3 NC −1 Horizontal component of net electric field at PO


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