1.

Calculate enthalpy of ionisation of `OH^(-)` ion. Given: `H_(2)O_((l)) rarr H_((aq))^(+)+OH_((aq))^(-), ? H^(0) =57.32 kJ` `H_(2_((g)))+1/2 O_(2_((g))) rarr H_(2)O_((l)), ? H^(0) =-285.83 kJ`

Answer» On adding given equations,
`H_(2_((g)))+1/2 O_(2_((g))) rarr H_((aq))^(+)+OH_((aq))^(-)`
`DeltaH^(@)=-228.51 kJ`
but for `H_((aq))^(+), DeltaH^(@)=0`
therefore heat of form ation of `OH^(-)` is
`-228.51 kJ`.


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