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Calculate entropy change when `10mol` of an ideal gas expands reversible and isothermally from an initial volume of `10L` to `100L` at `300K`. |
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Answer» `DeltaS = 2.3030 nR log_(10) ((V_(2))/(V_(1)))` `= 2.303 xx 10 xx 8.314 log_(10) ((100)/(10))` `= 191.24 J K^(-1)` |
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