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    				| 1. | Calculate heat of formation of `KOH(s)` using the following equations `K(s) +H_(2)O(l) +aq rarr KOH(aq)+1//2 H_(2)(g),DeltaH =- 48.0 kcal …(i)` `H_(2)(g) +1//2O_(2)(g) rarr H_(2)O(l),DeltaH =- 68.4 kcal …(ii)` `KOH(s) +(aq) rarr KOH(aq),DeltaH =- 14.0 kcal ....(iii)`A. `+102.83`B. `+130.85`C. `-102.83`D. `-130.85` | 
| Answer» Correct Answer - C `K_((s))+1/2 O_(2) +1/2 H_(2) rarr KOH_((s)) overset(H_(2)O)(rarr) KOH_((aq))` | |