Calculate length of seconds pendulum at a place where g= 9.78 m/s^2(me

1.	Calculate length of seconds pendulum at a place where g= 9.78 m/s^2(meter/ second square).
Answer» Answer: $\boxed{\sf <klux>LENGTH</klux> \ of \ seconds \ pendulum \ (<klux>L</klux>) = 0.99 \ m \approx 1 \ m}$ Given: Acceleration due to GRAVITY (g) = 9.78 m/s² To Find: Length of seconds pendulum (l) EXPLANATION: Time period (T) for one oscillation in seconds pendulum is 2 seconds. $\sf \implies T = 2 \ s$ Formula: $\boxed{ \bold{ \sf T = 2\pi \sqrt{ \frac{l}{g} } }}$ $\sf \implies l = \frac{T ^{2} g}{4 {\pi}^{2} }$ Substituting values of T & g in the equation: $\sf \implies l = \frac{ {2}^{2} \times 9.78 }{4 \times3.14 ^{2} }$ $\sf \implies l = \frac{ \cancel{4} \times 9.78}{ \cancel{4} \times 9.8596}$ $\sf \implies l = \frac{ 9.78}{ 9.8596}$ $\sf \implies l = 0.99 \: m \approx 1 \: m$ $\therefore$ Length of seconds pendulum (l) = 0.99 m ≈ 1 m