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Calculate pOH of a buffer solution containing 0.02M acetic acid and 0.02M sodium acetate? (given pKa = 4.74)1. 9.02. 6.03. 9.264. 4.0 |
Answer» Correct Answer - Option 3 : 9.26 Concept: (i) A buffer is an aqueous solution designed to maintain a constant pH, even when exposed to small amounts of acids or bases. (ii)Whether acidic (pH < 7) or basic (pH > 7), a buffer solution consists of a weak acid or base mixed with the salt of its conjugate base or acid, respectively. (iii)To calculate the specific pH of a given buffer, you need to use the Henderson-Hasselbalch equation for acidic buffers: \(pH = pka + \log \left( {\frac{{\left[ {A - } \right]}}{{\left[ {HA} \right]}}} \right)\) Where,Ka is the "dissociation constant" for the weak acid,[A-] is the concentration of conjugate base and [HA] is the concentration of the weak acid. pH + pOH = 14 Calculation: According to Henderson equation pH of acidic buffer is: \(pH = pka + \log \left( {\frac{{\left[ {A - } \right]}}{{\left[ {HA} \right]}}} \right)\) Here, pka = 4.74, [A-] = 0.02 and [HA] = 0.02 \(pH = 4.74 + \log \left( {\frac{{0.02}}{{0.02}}} \right) = 4.74\) ∵ We know that, pH + pOH = 14 So, pOH = 14 - pH = 14 - 4.74 = 9.26 |
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