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Calculate the area of the designed region in Fig. 12.34 common between the two quadrants of circles of radius 8 cm each. |
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Answer» as we can see that ar(2 quad) = area (square) + ar(design) ar(design) = 2* ar(quadrant) - ar(square) `= 2*1/4* pi r^2 - r^2` `= (pi r^2)/2 - r^2` `= r^2(pi/2 - 1)` `=8^2(1/2*22/7 - 1)` `= 64(11-7)/7` `= 256/7 cm^2` answer |
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