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Calculate the capacitance of the capacitor, if 10^12 electrons are transferred from one conductor to another of a capacitor and a potential difference of 10 V develops between the two conductors.(a) 1.6 × 10^-7 F(b) 160 × 10^-8 F(c) 16 × 10^-8 F(d) 1.6 × 10^-8 FThis question was addressed to me in an international level competition.The question is from Parallel Plate Capacitor topic in section Electrostatic Potential and Capacitance of Physics – Class 12 |
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Answer» RIGHT CHOICE is (d) 1.6 × 10^-8 F Best explanation: q = ne = 10^12 × 1.6 × 10^-19 = 1.6 × 10^-7 C. V = 10 V. C = \(\frac {q}{V}\) = 1.6 × \(\frac {1.6}{10^{-7}}\) C = 1.6 × 10^-8 F. |
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