Calculate the change in internal energy when `5g` of air is heated from internal energy when `5g` of air is heated from `0^(@)C "to" 2^(@)C`. Specific heat of air at constant volume is `0.172 cal//g//^(@)C`.

Calculate the change in internal energy when `5g` of air is heated fro

1.	Calculate the change in internal energy when `5g` of air is heated from internal energy when `5g` of air is heated from `0^(@)C "to" 2^(@)C`. Specific heat of air at constant volume is `0.172 cal//g//^(@)C`.
Answer» Here, `dU=?m= 5g, DeltaT= 2^(@)C` `C_(v)= 0.172 cal//g//^(@)C` `dQ=mC_(v) DeltaT= 5xx10.172xx2 cal` `=1.72xx4.2J= 7.2J` As air is heated at constant volume, `:. dW= 0` From first law of thermodynamics, `dU+dW=dQ` `dU=dQ-dW= 7.2-0= 7.2J`

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Calculate the change in internal energy when `5g` of air is heated from internal energy when `5g` of air is heated from `0^(@)C "to" 2^(@)C`. Specific heat of air at constant volume is `0.172 cal//g//^(@)C`.

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