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Calculate the coefficient of Correlation by karl person's method from the following dataX(6, 2,10,4,8,12) Y(9, 11,14,8,7,5) |
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Answer» Explanation: Let the assumed mean for the first variate x be 5 and that for the second variate y be 10. Here N=9 x y u=x−5 v=y−10 u 2 v 2 uv 1 6 −4 −4 16 16 16 2 5 −3 −5 9 25 15 3 7 −2 −3 4 9 6 4 9 −1 −1 1 1 1 5 8 0 −2 0 4 0 6 10 1 0 1 0 0 7 11 2 1 4 1 2 8 13 3 3 9 9 9 9 12 4 2 16 4 8 ∑u=0 ∑v=−9 ∑u 2 =60 ∑v 2 =69 ∑uv=57 ρ(x,y)= (∑u 2 − n (∑u) 2
). (∑v 2 − n (∑v) 2
)
∑uv− n 1
(∑u)(∑v)
= (60− 9 (0) 2
)
(60− 9 (−9) 2
)
57− 9 1
(0)(−9)
= 60
60
57
= 60 57
=0.95 |
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