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Calculate the difference between `DeltaE and DeltaH` for the following reaction at `27^(@)C` (in kcal) `C("graphite")+2H_(2)(g)toCH_(4)(g)`A. `-0.6`B. `-1.2`C. `+0.6`D. `+1.2` |
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Answer» Correct Answer - C `C("graphite")+2H_(2)(g) to CH_(4)(g)` `DeltaH=DeltaE+Deltan_(g)RT` `DeltaE-DeltaH=-Deltan_(g)RT` `DeltaE-DeltaH=-(-1)xx2xx300` `=600cal=0.6kcal` |
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