1.

Calculate the difference between `DeltaE and DeltaH` for the following reaction at `27^(@)C` (in kcal) `C("graphite")+2H_(2)(g)toCH_(4)(g)`A. `-0.6`B. `-1.2`C. `+0.6`D. `+1.2`

Answer» Correct Answer - C
`C("graphite")+2H_(2)(g) to CH_(4)(g)`
`DeltaH=DeltaE+Deltan_(g)RT`
`DeltaE-DeltaH=-Deltan_(g)RT`
`DeltaE-DeltaH=-(-1)xx2xx300`
`=600cal=0.6kcal`


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