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    				| 1. | Calculate the energy dissipated in kWh and J for a bulb of 250W. Which is used for 6 h | 
| Answer» -Power of the bulb = 250 WTime required = 6 hoursTo FIND :-The energy dissipated in kWh.The energy dissipated in J.Solution :-We know that,E = Energyp = Powert = TimeUsing the FORMULA,GIVEN that,Power (P) = 250 WTime (t) = 6 hours = 21600 secSubstituting their values,⇒ 250 = E/21600⇒ E = P × T⇒ E = 250 × 21600⇒ E = 5400000 J = 5.4 × 10⁶ JTherefore, the energy dissipated is 5.4 × 10⁶ J. | |