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Calculate the energy stored in the capacitor if the voltage across the capacitor is 20 V and capacitance value is 2 F.(a) 400 J(b) 200 J(c) 100 J(d) 50 JThe question was asked in an interview for internship.I need to ask this question from Electric Motors in chapter Braking of Electric Motors of Electric Drives

Answer»

The correct option is (a) 400 J

Explanation: The ENERGY STORED in the capacitor is .5×C×V^2. It is the TOTAL amount of energy stored in the capacitor in the STEADY state condition. E=.5×C×V^2=.5×2×20×20=400 J.



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