InterviewSolution
Saved Bookmarks
| 1. |
Calculate the enthalpy of the following reaction `:` `H_(2)C = CH_(2)(g) + H_(2)(g) rarr H_(3)C - CH_(3)(g)` The bond energies of `C-H,C-C,C=C` and `H-H` are 414,347,615 and 435 `kJ mol^(-1)` respectively |
| Answer» Correct Answer - `-125kJ mol^(-1)` | |