InterviewSolution
Saved Bookmarks
| 1. |
Calculate the entropy change of a process possessing ∆Ht = 2090 J mole-1 |
|
Answer» Given, Sn(α 13°C) - Sn(β 13°C) ∆Ht = 2090 J mol-1 ∆St = ∆Ht / Tt ∆St = 2090 / 286 ∆St = 7.307 J K-1 mol-1 |
|