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InterviewSolution
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Calculate the equilibrium constant for the reaction given below at `400K`, if `DeltaH^(Theta) = 77.2 kJ mol^(-1)` and `DeltaS^(Theta) = 122 J K^(-1) mol^(-1)` `PCI_(5)(g) rarr PCI_(3)(g) +CI_(2)(g)` |
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Answer» `DeltaH^(Theta) = 77.2 mol^(-1)` `DeltaS^(Theta) = 122 J K^(-1) mol^(-1)` `T = 400K` `:. DeltaG^(Theta) - T DeltaS^(Theta)` `DeltaG^(Theta) = 77200 - 400 xx122 = 28400 J` Also, we have `-DeltaG^(Theta) = 2.303 RT log_(10)K_(c)` where `K_(c)` is equilibrium constant `:. -28400 = 2.303 xx 8.314 xx 400 log_(10)K_(c)` `:. K_(c) = 1.958 xx 10^(-4)` |
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