1.

Calculate the force of attraction between two charges +4 coulumb and -4 coulumb seperated by 8×10 to the power 3 m​

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Answer:

QUESTION:

calculate the force of attraction between TWO charges +4 coulumb and -4 coulumb seperated by 8×10^3 m

GIVEN:

  • q1=4 coulomb
  • q2=-4 coulomb
  • r=8×10^3 m

TO FIND:

electrostatic force of attraction, f

FORMULA:

according to coulomb's law of electrostatics,

f=(Kq1q2)/r^2

where,

  • f..... electrostatic force
  • q1 and q2 are charges
  • k is the proportionality constant whose value is 9×10^9 C^2N^-2m^-2
  • r.....distance of seperation

SOLUTION:

f = \frac{kq1q2}{ {r}^{2} } \\ \\ = \frac{9 \times {10}^{9} \times (4)( - 4) }{ {(8 \times {10}^{3}) }^{2} } \\ \\ = \frac{ - 144 \times {10}^{9} }{64 \times {10}^{6} } \\ \\ = - 2.25 \times {10}^{3} \\ \\ = - 2250 \: newton

force is 2250 Newton or 2.25 kilo Newton

the negative sign indicates that the force is attractive

NOTE:

  • attractive force EXIST between two oppositely CHARGED particles.

  • repulsive force exist between two same charged PARTICLE


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