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InterviewSolution
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Calculate the half life of the first-order reaction: `C_(2)H_(4)O(g) rarr CH_(4)(g)+CO(g)` The initial pressure of `C_(2)H_(4)O(g)` is `80 mm` and the total pressure at the end of `20 min` is `120 mm`.A. `40 min`B. `120 min`C. `20 min`D. `80 min` |
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Answer» Correct Answer - C `{:(,C_(2)H_(4)O(g) ,rarr,CH_(4)(g)+,CO(g)),(t=0,P_(0),,0,0),(t=t,P_(0)-x,,x,2x):}` Total pressure `(P_(t)) = P_(0) - x + x + x = P_(0) + x` `P_(0) = 80 mm` `P_(0) + x = 120 mm` `:. x = 120 - 80 = 40 mm` `k = (2.203)/(20)log.(P_(0))/(P_(0)-x) = (2.3)/(20)log.(80)/(80-40)` `k = (2.3 xx 0.3)/(20) rArr t_(1//2) = (0.69)/(k) = (0.69 xx 20)/(0.69) = 20 min` |
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