InterviewSolution
Saved Bookmarks
| 1. |
Calculate the heat of combustion of benzene form the following data: a. `6C(s) +3H_(2)(g) rarr C_(6)H_(6)(l), DeltaH = 49.0 kJ` b. `H_(2)(g) +1//2O_(2)(g) rarr H_(2)O(l), DeltaH =- 285.8 kJ` c. `C(s) +O_(2) (g) rarr CO_(2)(g), DeltaH =- 389.3 kJ` |
|
Answer» To calculate `DeltaH` of the following: `C_(6)H_(6)(l) +(15)/(2)O_(2)(g) rarr 6CO_(2)(g) -3H_(2)O(l) DeltaH = ?` `DeltaH = 3DeltaH_(2) +6DeltaH_(3) - DeltaH_(2)` `=3 xx 285.8 +6 xx -389.3 - 49.0` `=- 857.4 - 2335.8 - 49` `=- 3242.2 kJ mol^(-1)` |
|