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Calculate the I0 avg for Single-phase Half Wave rectifier for R-L load using the data: Vm=56 V, ∝=15°, β=30°, R=2 Ω.(a) .56 A(b) .44 A(c) .26 A(d) .89 AThis question was posed to me in class test.The origin of the question is Solid-State Switching Circuits topic in section Introduction to Solid-State Switching Circuits of Electric Drives |
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Answer» CORRECT answer is (a) .56 A The explanation is: In Half-wave controlled rectifier, the AVERAGE value of the CURRENT is Vm(cos(∝)-cos(β))÷2πR=56(cos(15°)- cos(30°))÷12.56=.44 A. The thyristor will conduct from ∝ to β. |
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