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Calculate the I0 r.m.s for Single-phase Half Wave rectifier for R-L load (Highly inductive) using the data: Vm=110 V, ∝=16°, β=31°, R=1 Ω.(a) 4.56 A(b) 1.82 A(c) 4.81 A(d) 9.15 AI have been asked this question during an interview for a job.Question is taken from Solid-State Switching Circuits in chapter Introduction to Solid-State Switching Circuits of Electric Drives

Answer» RIGHT option is (B) 1.82 A

The explanation: In Half-wave CONTROLLED rectifier, the r.m.s value of the current is Vm(cos(∝) – cos(β))÷2πR=110(cos(16°) – cos(31°))÷6.28=1.82 A. The thyristor will CONDUCT from ∝ to β.


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