InterviewSolution
Saved Bookmarks
| 1. |
Calculate the length of a second's pendulum on the surface of moon where acceleration due to gravity is 1/6ththe acceleration due to gravity on the earth [g 9.8 ms^-2) |
|
Answer» Is there any value for time given? Ok this problem ca be solved if time T is assumed to be 2s 1/6 x 9.8 x 2^2/4 pi ^2 |
|