1.

Calculate the length of a second's pendulum on the surface of moon where acceleration due to gravity is 1/6ththe acceleration due to gravity on the earth [g 9.8 ms^-2)

Answer»

Is there any value for time given?

Ok this problem ca be solved if time T is assumed to be 2s

1/6 x 9.8 x 2^2/4 pi ^2



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