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Calculate the longest wavelength that can an electron from the first bohr given `E_(1) = 13.6 eV` |
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Answer» The photon capable of removing an electron from the first bohr orbit posses energy `= 13.6eV` `= 13.6 xx 1.602 xx 10^(-19) J` `= 21.787 xx 10^(-19) J` `," E = (hc)/(lambda)` `21.787 xx 10^(-19) = (6.625 xx 10^(-34) xx 3.0 xx 10^(8))/(lambda)` `:. lambda = 912.24 xx 10^(-10)m = 912.24 Å` Energy of photon `E = Nhv = (Nhv)/(lambda)` :. Number of photon electrons emitted per minut `(N) = (E lambda)/(hc)` `= (6000 J xx 300 xx 10^(-9)m)/(6.626 xx 10^(-34) J s xx 3 xx 10^(8) ms^(-1))` `= 9.05 xx 10^(22)`photons |
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