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Calculate the mass of the following: (i) 0.5 mole of N_(2) gas (mass from mole of molecule) (ii) 0.5 mole of N atoms (mass from mole of atom) (iii) 3.011 xx 10^(23) number of N atoms (mass from number) (iv) 6.022 xx 10^(23) number of N_(2) molecules (mass from number) |
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Answer» Solution :(i) mass = `"molar mass" xx "number of moles"` `IMPLIES m = M xx n = 28 xx 0.5` = 14 g (ii) mass = `"molar mass" xx "number of moles"` `implies m=M xx n = 14 xx 0.5` = 7 g (iii) The number of moles (n)= `("given number of particles")/("Avogadro number")` `=(N)/(N_(0))= (3.011 xx 10^(23))/(6.022 xx 10^(23))` `implies m = M xx n = 14 xx (3.011 xx 10^(23))/(6.022 xx 10^(23)) = 14 xx 0.5` = 7G (iv) `n = (N)/(N_(0))` `implies m = M xx (N)/(N_(0))` `= 28 xx (6.022 xx 10^(23))/(6.022 xx 10^(23)) = 28 xx 1` = 28 g |
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