1.

Calculate the mass of the following: (i) 0.5 mole of N_(2) gas (mass from mole of molecule) (ii) 0.5 mole of N atoms (mass from mole of atom) (iii) 3.011 xx 10^(23) number of N atoms (mass from number) (iv) 6.022 xx 10^(23) number of N_(2) molecules (mass from number)

Answer»

Solution :(i) mass = `"molar mass" xx "number of moles"`
`IMPLIES m = M xx n = 28 xx 0.5` = 14 g
(ii) mass = `"molar mass" xx "number of moles"`
`implies m=M xx n = 14 xx 0.5` = 7 g
(iii) The number of moles (n)= `("given number of particles")/("Avogadro number")`
`=(N)/(N_(0))= (3.011 xx 10^(23))/(6.022 xx 10^(23))`
`implies m = M xx n = 14 xx (3.011 xx 10^(23))/(6.022 xx 10^(23)) = 14 xx 0.5`
= 7G
(iv) `n = (N)/(N_(0))`
`implies m = M xx (N)/(N_(0))`
`= 28 xx (6.022 xx 10^(23))/(6.022 xx 10^(23)) = 28 xx 1`
= 28 g


Discussion

No Comment Found