Calculate the maximum work done in expanding `16g` of oxygen at `300K` occupying volume of `5dm^(3)` and isothermally untill the volume become `25dm^(3)`?

Calculate the maximum work done in expanding `16g` of oxygen at `300K`

1.	Calculate the maximum work done in expanding `16g` of oxygen at `300K` occupying volume of `5dm^(3)` and isothermally untill the volume become `25dm^(3)`?
Answer» Since, it is the maximum work, thus, the process is reversible. `nO_(2) = (w)/(m) = (16)/(32),R = 8.314J`, `T = 300K, V_(1) = 5dm^(3), V_(2) = 25dm^(3)` `w =- 2.303nRT log_(10). (V_(2))/(V_(1))` `=- 2.303 xx (16)/(32) xx 8.314 xx 300 log_(10). (25)/(5)` `= - 2.01 xx 10^(3)J`

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Calculate the maximum work done in expanding `16g` of oxygen at `300K` occupying volume of `5dm^(3)` and isothermally untill the volume become `25dm^(3)`?

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