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Calculate the moment of inertia of the hollow cylinder having a mass of 78 kg and radius of 49 cm.(a) 9.363 kgm^2(b) 9.265 kgm^2(c) 9.787 kgm^2(d) 9.568 kgm^2The question was posed to me in unit test.This interesting question is from Modified Speed Torque Characteristics of DC Series Motors in section Characteristics of DC & AC Motors of Electric Drives

Answer»

The correct option is (a) 9.363 kgm^2

The best I can explain: The moment of inertia of the hollow cylinder can be calculated using the formula I=miri^2÷2. The mass of the hollow cylinder and radius is given. I=(78)×.5×(.49)^2=9.363 kgm^2. It DEPENDS UPON the orientation of the rotational AXIS.



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