1.

Calculate the no. of `alpha-` and `beta-` particles given during the change: `._(93)^(237)Np rarr ._(83)^(209)Bi` Also report the nature and name of this radioactive series.

Answer» `._(93)Np^(237) rarr ._(83)Bi^(209) + a_(2) He^(4) + b _(-1)e^(0)`
Where `a` amd `b` are `alpha` and `beta-` particles given out during change.
Equating mass number: `237 = 209 + 4a + 0 xx b`
`a = 7`
Equating atomic number, keeping `a = 7`
`93 = 83 + 2xx7 + b xx (-1)`
`b = 4`
Thus `7 alpha`, and `4beta-` are given out during the change also `237//4 = 59` with remainder 1 and thus it is `(4n + 1)` series, the artificial radioactive sereis also called as napunium series with `n = 59`.


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