1.

Calculate the no of e present in 7g of Si ⁴+​

Answer»

tion:first the number of molesso,float moles= 7.0/28.0855;PRINTF("Number of atoms = %dNa",moles)here NA is Avagadro's Number ,i.e,6.022x10^23.U can also get to this in this manner :-1 MOLE of SI contains 6.022x10^23 atoms also 1 mole of Si equals 28.0855 g of SiSo ,28.0855 g of Si contains 6.022x10^23 atoms Hence,7 g of Si contains (6.022x10^23/28.0855)*7 atoms



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