1.

Calculate the number of neutrons present in the nucleus of an element X which is represented as .^(31)X_(15).

Answer»

Solution :`.^(31)X_(15)` INDICATE that No FO protons = 15 and mass NUMBER = 31
Mass number = No. of proton + No. of Neutron = 31
No of neutron = 31 - number of protons
`= 31-15=16`


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