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Calculate the number of neutrons present in the nucleus of an element X which is represented as .^(31)X_(15). |
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Answer» Solution :`.^(31)X_(15)` INDICATE that No FO protons = 15 and mass NUMBER = 31 Mass number = No. of proton + No. of Neutron = 31 No of neutron = 31 - number of protons `= 31-15=16` |
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