1.

Calculate the percentage of elements in the following compound: Ammonia

Answer»

Solution :Molecular formula of AMMONIA is `NH_(3)`. Molecular mass of `NH_(3) = (1 xx "ATOMIC mass of N") + (3 xx "atomic mass of H")`
`= (1 xx 14) + (3 xx 1)`
= 14 + 3 = 17 `g//"MOLE"`
Thus, in 17g `NH_(3)`, 14g of N and 3g of H is present.
Percentage of nitrogen = `(14g)/(17g) xx 100` =82.35
Percentage of HYDROGEN =`(3g)/(17g) xx 100` = 17.65
Nitrogen : 82.35 % and Hydrogen : 17.65%


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