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Calculate the percentage of elements in the following compound: K_(2)SO_(4) |
Answer» SOLUTION :Molecular mass of `(K_(2)SO_(4)) = (2 xx "atomic mass of K") + (1 xx "atomic mass of S") + (4 xx "atomic mass of O")` `= (2 xx 39) + (1 xx 32) + (4 xx 16)` = 78 + 32 + 64 = 174 `:.` 174 g of `K_(2)SO_(4)` contains 78 g of POTASSIUM. 32 g of SULPHUR and 64 g of oxygen Percentage of potassium = `(78 g)/(174 g) xx 100 ~~ 44.83` Percentage of sulphur = `(32 g)/(174 g) xx 100 ~~ 18.39` Percentage of oxygen= `(64 g)/(174 g) xx 100 ~~ 36.78` Polassium : 44.83 %, Sulphur: 18.39% and Oxygen : 36.78 % |
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