1.

Calculate the pH of 1xx10^(-4) molar solution of NaOH.

Answer»

Solution :NAOH is a strong BASE and dissociates in its solution as:
`NaOH_((aq))toNa_((aq))^(+)+OH^_(aq)^(-)`
One mole of NaOH would one mole of `OH^(-)` ions.Therefore,`[OH^(-)]=1xx10^(-4)mol`,`litre^(-1)`
pOH=`-log_(10)[OH^(-)]=-log_(10)xx[10^(-4)]` Since ,pH+pOH=14
pH=14-pOH=14-4
10


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