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Calculate the pressure at a depthe 'h' in a liquid. |
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Answer» Solution :1. LET us consider a container which contains a liquid in it of density`'rho'` 2. Consider cylindrical column of height 'h' from the surface of the liquid of cross sectional area "A". 3. The volume of the liquid column V = Ah `"MASS"="Volume"xx"density"` `rArrm=Ahrho` `"Weight W"=mg=Ahrhog` From Newton's law the force on the liquid column is zero, because it is at REST. 4. The forces acting on the WATER column are a. Weight (W), vertically down b. Force on the surface due to atmospheric pressure `(P_(@)A)` acting vertically down. c. Froce on the botton surface of the column due to static pressure of liquid (PA), acting vertically up. 5. From Newton's law we get `PA=P_(@)A+WrArrPA=P_(@)A+hrhogArArrPA=A(P_(@)+hrhog)` `thereforeP=P_(@)+hrhog` P = Pressure at depth 'h' from the surface of the liquid `P_(@)`= Atmospheric pressure `therefore`The pressure inside the liquid at a constant depth is constant depth is constant.
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