Calculate the rate of loss of heat through a glass window of area `1000 cm^(2)` and thickness 0.4 cm when temperature inside is `37^(@)C` and outside is `-5^@)C` . Coefficient of thermal conductivity of glass is `2.2 xx 10^(-3) cal s^(-1) cm^(-1) K^(-1)`.

Calculate the rate of loss of heat through a glass window of area `100

1.	Calculate the rate of loss of heat through a glass window of area `1000 cm^(2)` and thickness 0.4 cm when temperature inside is `37^(@)C` and outside is `-5^@)C` . Coefficient of thermal conductivity of glass is `2.2 xx 10^(-3) cal s^(-1) cm^(-1) K^(-1)`.
Answer» Here, `A =1000 cm^(2), Delta x = 0.4 cm`, `T_(1) = 37^(@)C = 273 + 37 = 310 K` `T_(2) = 273 - 5 = 268 K`, `K = 2.2 xx 10^(-3) cal s^(-1) cm^(-1) K^(-1)` Rate of loss of heat `=(Delta Q)/(Delta t) = (KA Delta T)/(Delta x) = (KA(T_(1)-T_(2)))/(Delta x)` `=((2.2 xx 10^(-3)) xx 1000 xx (310 - 268))/(0.4)` `=231 cal s^(-1)`.

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Calculate the rate of loss of heat through a glass window of area `1000 cm^(2)` and thickness 0.4 cm when temperature inside is `37^(@)C` and outside is `-5^@)C` . Coefficient of thermal conductivity of glass is `2.2 xx 10^(-3) cal s^(-1) cm^(-1) K^(-1)`.

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