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Calculate the reduced mass of hydrogen molecule (H).Atomic mass of hydrogen is 1.7 x 10-27 Kg. |
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Answer» ke2/r2= mv2/r Where ke2/r2is the Coulomb's force and mv2/r is thecentripetalforce of the electron around the nucleus you know from Bohr's postulate mvr = nh/2π Combine the two equations. What is the value of the radius of the first orbit ? r= Plank's constant h= 6.624 10-34Js electron mass me= 9.11 10-31Kg electron charge e= -1.6 10-19C Coulomb's constant k=8.99 109m2N/C2 ke2/r2= mv2/r 3rdBohr's postulate mvr = nh/2Π v = nh/2Πmr ke2/r2= mn2h2/r4Πm2r2 r = n2h2/k4Π2me2 r = 0.53 Angstrom |
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