1.

Calculate the standard free energy change for the reaction, `H_(2)(g) + I_(2)(g) rarr 2HI(g), DeltaH^(@) = + 51.9 kJ` Given that the standard entropies `(S^(@))` of `H_(2), I_(2)` and HI are 130.6, 116.7 and 206.3 J `K^(-1) mol^(-1)` respectively. Predict whether the reaction is feasible at the standard state or not.

Answer» Correct Answer - `DeltaG^(@) = + 2640. 6 Jmol^(-1)` . Not feasible
`Delta_(r)S^(@)= 2xxS_((HI))^(@) - [ S_((H_(2)))^(@) +S_((I_(2)))^(@)]= 2 xx 206.3 - ( 130.6+ 116.7) = 165.3 J mol^(-1)`
`Delta_(r)G^(@) = Delta_(r)H^(@) - T Delta_(r)S^(@) = 51900 - 298 xx 165.3 = 2640.6 J mol^(-1)`


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