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Calculate the time a body takes to return to its original position when thrown vertically upward with a velocity of 30 m/s. |
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Answer» Time taken to return to original position is 6 seconds. Explanation: According to the question the body is thrown vertically upwards with velocity u=30m/s now when the body ATTAINS maximum height its final velocity will become zero i.e v=0 we know that according to Newton's laws of motion v=u+at=> 0=30+(-10)(t) ASSUMING g≈10m/s² -30/-10=t t=3s but this is the time taken to reach maximum height to calculate the time taken for the body to return we must DOUBLE it. i.e T=2t=6s |
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