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Calculate the total cost of running the following electrical devices in the month ofSeptember, if the rate of 1 unit of electricity is 6.00.(i) Electric heater of 1000 W for 5 hours daily.(ii) Electric refrigerator of 400 W for 10 hours daily.Cl1 |
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Answer» I)P1= 1000 W /1000 = 1 kW t1= 5 h ii) P2= 400 W / 1000 = 0.4 kW t2= 10 h No. of days, n = 30 E1= P1x t1x n = 1 kW x 5 h x 30 = 150 kWh E2= P2x t2x n = 0.4kW × 10 h × 30 = 120 kWh Total energy = (150 + 120) kWh = 270 kWh Total cost = 270 x 6 = Rs. 1620 Like if you find it useful |
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