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Calculate the total heat dissipated in a resistor of 12 Ω when 9.2 A current flows through it.(a) 2.01 KW(b) 3.44 KW(c) 1.01 KW(d) 2.48 KWI got this question in unit test.The origin of the question is Energy Relations During Starting topic in division Starting of Electric Drives

Answer»

Correct answer is (c) 1.01 KW

Explanation: The RESISTOR is a linear ELEMENT. It only absorbs real POWER and dissipates it in the form of heat. The voltage and CURRENT are in the same phase in CASE of the resistor so the angle between V & I is 90°. P=I^2R=9.2×9.2×12=1.01 kW.



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