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Calculate the total number of ions in 0.585 g of sodium chloride . |
Answer» Solution :Gram formula mass of NaCl = 23 + `35*5 = 58*5` g `58.5` g of NaCl haveions = `2 XX N_(A)` 58.5 g of NaCl have ions = `2 xx N_(A) = (0.585)/(58*5) = 0*02 xx N_(A)` `=0*02 xx 6*022 xx 10^(23)` `= 1*20 xx 10^(22)` ions |
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